Where is the near point of an eye for which a contact lens with a power of +2.55 diopters is prescribed? where is the far point of an eye for which a contact lens with a power of

(a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

Explanation:

Given that,

Power = 2.55 D

Object distance = 25 cm for near point

Object distance = ∞ for far point

Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D  is prescribed for distant vision?

(a) We need to calculate the focal length

Using formula of power

Put the value into the formula

We need to calculate the image distance

Using formula of lens

Put the value into the formula

The eye's near point is 68.98 cm from the eye.

(b). We need to calculate the focal length

Using formula of power

Put the value into the formula

We need to calculate the image distance

Using formula of lens

Put the value into the formula

The eye's far point is 33.33 cm from the eye.

Hence, (a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.