What horizontally-applied force will accelerate a crate of mass 400 kg at 1 meter per second per second across a factory floor against a friction force of half its weight?

The horizontally applied force = 2360 N

Explanation:

Force: Force can be defined as the product of mass and acceleration. the S.I unit of force is Newton (N)

Fh = Fr + ma Equation 1

Where Fh = horizontally applied force, Fr = friction force, m = mass of the crate, a = acceleration of the crate.

Given: m = 400 kg, a = 1 m/s²

Fr = 1/2 W, W = mg  ⇒W = 400×9.8 = 3920 N

∴Fr = 1/2(3920), Fr = 1960 N

Substituting these values into equation 1

Fh = 1960 + 400×1

Fh = 1960 + 400

Fh = 2360 N

Therefore the horizontally applied force = 2360 N

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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