Amechanic turns a wrench using a force of 27.00 n at a distance of 16.00 cm from the rotation axis. the force is perpendicular to the wrench handle. what magnitude torque does she apply to the wrench?

4.32Nm

Explanation:

The magnitude of the torque will be the product of the force and its perpendicular distance from the force.

Force = 27N

Perpendicular distance = 16cm = 0.16m

Torque = 27×0.16

Torque = 4.32Nm

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14