Aweight of 720 n rests on a lever at a point 0.50 m from a support. on the same side of the support, at a distance of 3.0 m from it, an upward force with magnitude f is applied. neglect the weight of the board itself. if the system is in equilibrium, what is f?

120 N

Explanation:

weight (w) = 720 N

distance of weight from the support (s) = 0.5 m

upward acting force (F) = ?

distance of upward force from the support (L) = 3 m

If the system is in equilibrium, what is F?

since the system is in equilibrium Σ Torque = 0

where

        -FL + ws = 0

        - (F x 3) + (720 x 0.5) = 0

          -3F + 360 = 0

           F = 360/3 = 120 N

im not to sure what it is