A5.00 l volume of methane gas is cooled from 298 k to 149 k. if the pressure remains constant, what is the final volume in liters?

The final volume of methane gas = 2.5 L

Explanation:

Charles' Law: Charles'  law states that the volume of a given mass of gas is directly proportional to it's absolute temperature provided the pressure remains constant.

From Charles' law

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation above,

V₂ = (V₁/T₁)T₂ equation 1

Where V₁ = initial Volume, T₁ Initial Temperature, V₂ = Final Volume, T₂ = final Temperature.

Given: V₁ = 5.00 L, T₁ = 298 K, T₂ = 148 K

Substituting these values into equation 1

V₂ = (5.00/298)149

V₂ = 2.5 L.

Therefore the final volume of methane gas = 2.5 L

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form