Find the pressure necessary to change a volume of steel by
1.0 percent. express the pressure in terms of atmospheric
pressure units 1 bar = 10°n/m², where bulk' modulus of
steel is 160 x 10' n/m².

160×10⁶ bar

Explanation:

Bulk modulus is defined as:

K = -V ΔP / ΔV

where V is the initial volume,

ΔP is the change in pressure,

and ΔV is the change in volume.

Given:

K = 160×10⁹ Pa

ΔV = -0.01V

160×10⁹ Pa = -V ΔP / (-0.01V)

160×10⁹ Pa = ΔP / 0.01

ΔP = 160×10¹¹ Pa

ΔP = 160×10⁶ bar

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: