The hubble space telescope orbits the earth at an approximate altitude of 612 km. its mass is 11,100 kg and the mass of the earth is 5.97×1024 kg. the earth's average radius is 6.38×106 m. what is the magnitude of the gravitational force that the earth exerts on the hubble?

magnitude of the gravitational force is 9.04 × N

Explanation:

given data

altitude = A = 612 km = 612000 m

mass M = 11,100 kg

mass of the Earth m = 5.97 × kg

Earth average radius = 6.38 ×  m

to find out

magnitude of the gravitational force

solution

first we get here distance from space to centre of earth that is

distance = altitude + earth radius

distance = 612000  +  6.38 ×  m

distance = 6.99 ×  m  

so now we get here  magnitude of the gravitational force that is express as

magnitude of the gravitational force F =   ...........1

here G is gravitational constant  that is 6.67 × Nm² /kg and M is mass of space and m is mass of earth

put here all value we get

F =

F =

F = 9.04 × N

so magnitude of the gravitational force is 9.04 × N

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min