In preparation for building a space station, an astronaut removes a self-telescoping uniform rod from the cargo bay and releases it, not noticing that he gave it an angular speed of 0.0500 radians per second. the pole is 3.00 meters long. a catch slips, and the pole spring retracts it into a shorter 1.50 meter long uniform pole about a minute after the astronaut releases it. find the angular speed after the catch slips.

To solve this problem it is necessary to apply the concepts related to the conservation of angular momentum. This can be expressed mathematically as a function of inertia and angular velocity, that is:

Where,

I = Moment of Inertia

= Angular Velocity

For the given object the moment of inertia is equivalent to

Considering that the moment of inertia varies according to distance, and that there are two of these without altering the mass we will finally have to

Our values are given as,

Replacing we have,

Therefore the angular speed after the catch slips is 0.2rad/s

terd muffin is the correct answer

double the distance = divide strength by 4