Acar drives straight down toward the bottom of a valley and up the other side on a road whose bottom has a radius of curvature of 115 m. at the very bottom, the normal force on the driver is twice his weight. at what speed was the car traveling?

33.58794 m/s

Explanation:

= Cenrtipetal force =

m = Mass of car

r = Radius of curvature = 115 m

g = Acceleration due to gravity = 9.81 m/s²

The normal force is given by

At the bottom N = 2N

The car was traveling at the speed of 33.58794 m/s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

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