Abody of mass 2kg is thrown up with a speed of 25m/s. find its maximum potential
energy.

Maximum potential energy of body is 625 joule

Explanation: Maximum potential energy = initial kinetic energy

= 0.5 mv^2

= 0.5 multiply 2 kg multiply (25 m/s)^2

=625 joule

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west