An electron is accelerated uniformly at a rate of 25,000 km/s from rest in an accelerator, over a distance of 125 km. what is the final velocity of the electron?

2500km/s

Explanation:

use equation wich conects distance and  acceleration:

S=Vst+at²/2

Vs=0km/s(from rest)

S=at²/2

S2=at²

t=√2S/a

t=√2*125km/25000 km/s²

t=0.1s

Vf --final velocity

Vs-- start velocity

a=Vf-Vs/t

at=Vf-Vs

Vs=0Km/s

at=Vf

25000Km/s*0.1s=Vf

Vf=2500Km/s

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: