Physics, 21.12.2019 04:31 bigmess559

Capacitor plates have area 5.00 cm^2 and separation 2.00 mm. the plates are in a vacuum. the charging current i_c has a constant value of 1.80 ma. at t = 0 the charge on the plates is zero. (a) calculate the charge on the plates, the electric field between the plates, and the potential difference between the plates when t = 0.500 ms. (b) calculate de/dt, the time rate of change of the electric field between the plates. does de/dt vary in time? (c) calculate the displacement current density jd between the plates, and from this the total displacement current i_c. how do i_c and i_d compare?

Answers: 1

Show answers

Answers

Answer from: deku6

a) Q = $9*10^{-10}$ C; E = 2.03*10^5 V/m; V = 406.8 V

b) dE/dt = $4.07*10^{11}$ V/(m.s); No

c) J_d = 3.6 A/m^2 ; Equal

Explanation:

Given parameters are:

Area, A = 5 cm^2

Separation, d = 2 mm

Changing current, i_c = 1.8 mA

At time t = 0 the charge Q_0 = 0

a) Here, we are asked to find charge, Q, electric field, E, and potential difference, V at time t = 0.5 $\mu s$

$Q = i_ct = 1.8*10^{-3}*5*10^{-7} = 9*10^{-10}$ C

$E = \sigma/\epsilon_0 = (Q/A)/\epsilon_0 = (9*10^{-10}/5*10^{-4})/(8.85*10^{-12}) = 2.03*10^5$ $\frac{V}{m}$

$V = Ed = 2.03*10^{-5}*2*10^{-3} = 406.8$ V

b) $E = (Q/A)/\epsilon_0$

⇒ $\frac{dE}{dt} = \frac{dQ}{dt} \frac{1}{\epsilon_0 A} = \frac{i_c}{\epsilon_0 A} = \frac{1.8*10^{-3}}{5*10^{-4}*8.85*10^{-12}} = 4.07*10^{11}$ V/(m.s)

No, it is constant that does not vary in time because i_c is constant.

c) the displacement current density, $J_d = \epsilon_0\frac{dE}{dt} = \epsilon_0\frac{i_c}{\epsilon_0 A} = i_c/A$

⇒ $J_d = 1.8*10^{-3}/(5*10^{-4}) = 3.6$ A/m^2

$i_d =J_dA = 3.6*5*10^{-4} = 1.8*10^{-3}$ A

So, i_c and i_d are equal.

Answer from: Kookiexperfect9420

The charge on the plates $Q=9 * 10^{-10} C ; E=2.03 * 10^{5} \mathrm{~V} / \mathrm{m} ; \mathrm{V}=406.8 \mathrm{~V}$

The time rate of change of the electric field between the plates $\mathrm{dE} / \mathrm{dt}=4.07 * 10^{11} \mathrm{~V} /(\mathrm{m} . \mathrm{s}) ; \mathrm{No}$

The displacement current density jD between the plates $J_{d}=3.6 \mathrm{~A} / \mathrm{m}^{2}$ Equals

Explanation:

Given parameters are:

Area, $$A=5cm^{2}$

Separation, $\mathrm{d}=2 \mathrm{~mm}$

Changing current, $i_{c}=1.8 \mathrm{~mA}$

At time $\mathrm{t}=0$ the charge $Q_{0}=0$

a) Here, we are asked to find charge, $Q$ , electric field, $E$ and potential difference, $\mathrm{V}$ at time $\mathrm{t}=0.5 \mu \mathrm{s}$

$Q=i_{c} t=1.8 \times10^{-3} \times 5 \times10^{-7}=9 \times10^{-10} \mathrm{C}$

$E=\sigma / \epsilon_{0}=(Q / A) / \epsilon_{0}=\left(9 \times10^{-10} / 5 \times10^{-4}\right) /\left(8.85\times 10^{-12}\right)=2.03 \times10^{5} \frac{\mathrm{V}}{m}$

$V=E d=2.03 \times10^{-5} \times2\times 10^{-3}=406.8 \mathrm{~V}$

b) $E=(Q / A) / \epsilon_{0}$

$\Rightarrow \frac{d E}{d t}=\frac{d Q}{d t} \frac{1}{\epsilon_{0} A}=\frac{i_{c}}{\epsilon_{0} A}=\frac{1.8 \times10^{-3}}{5\times 10^{-4} \times 8.85 \times 10^{-12}}=4.07 \times 10^{11} \mathrm{~V} /(\mathrm{m} . \mathrm{S})$

No, it is constant that does not vary in time because is constant.

c) the displacement current density, $J_{d}=\epsilon_{0} \frac{d E}{d t}=\epsilon_{0} \frac{i_{c}}{\epsilon_{0} A}=i_{c} / A$

$\Rightarrow J_{d}=1.8 \times 10^{-3} /\left(5 \times10^{-4}\right)=3.6 \mathrm{~A} / \mathrm{m}^{2}$

$i_{d}=J_{d} A=3.6 \times5 \times10^{-4}=1.8\times 10^{-3} \mathrm{~A}$

So, $i_{c}$ and $i_{d}$ are equal.

To know more about

Answer from: Quest

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

Answer from: Quest

distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

slope of a graph = change in value of y -axis / change in values of x -axis

comparing both the equations

change in value of y -axis = change in position

change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

Another question on Physics

Physics, 22.06.2019 14:30

Aweight lifter raises a 1600 n barbell to a height of 2.0 meters. how much work was done? w = fd a) 30 joules b) 3000 joules c) 320 joules d) 3200 joules

Answers: 2

Answer

Physics, 22.06.2019 14:30

Aracecar driver has to hold on tightly when going around a banked curve. approximately what is the centripetal force on a 2220.0 kg car going around a circle with a diameter of 190.0 meters at 25.0 m/s?

Answers: 1

Answer

Physics, 22.06.2019 20:00

In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their backs against the wall. the cylinder begins to rotate about a vertical axis. then the floor on which the passengers are standing suddenly drops away! if all goes well, the passengers will “stick” to the wall and not slide. clothing has a static coefficient of friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. part a what is the minimum rotational frequency, in rpm, for which the ride is safe? express your answer using two significant figures. f f = rpm

Answers: 1

Answer

Physics, 22.06.2019 20:20

The base of a 50-meter tower is at the origin; the base of a 50-meter tree is at (0, 50, 0). the ground is flat and the z-axis points upward. the following parametric equations describe the motion of six projectiles each launched at time t = 0 in seconds. (i) r (t) = (50 + t2)k (ii) r (t) = 2t2 j + 2t2k (iii) r (t) = 50 i + 50 j + (50 − t2)k (iv) r (t) = 2t j + (50 − t2)k (v) r (t) = (50 − 2t) i + 2t j + (50 − t)k (vi) r (t) = t i + t j + tk (a) which projectile is launched from the top of the tower and goes downward? at time t = , the projectile hits the ground at point (x, y, z) = . (b) which projectile hits the top of the tree?

Answers: 2

Answer

You know the right answer?

Capacitor plates have area 5.00 cm^2 and separation 2.00 mm. the plates are in a vacuum. the chargin...

Questions