Asheet of gold weighing 12.0 g with an initial temperature of 15 °c is placed flat on a 20.0g plate of iron that has been heated to 55°c. what is the final temperature of both pieces of metal? the specific heat of iron is 0.449 j/g°c and the specific heat of gold is 0.129 j/g°c.

49.12 °C

Explanation:

= mass of gold sheet = 12 g

= specific heat of gold = 0.129 J/g°C

= initial temperature of gold sheet = 15 °C

= mass of iron sheet = 20 g

= specific heat of iron = 0.449 J/g°C

= initial temperature of iron sheet = 55 °C

= Final equilibrium temperature

Using conservation of heat

double the distance = divide strength by 4