Arigid rod is rotating at a constant angular speed about an axis that is perpendicular to one end of the rod. a small ball is fixed to the rod at a distance that is 12 cm from the axis. the centripetal force acting on this ball is 1.7 n. what would be the centripetal force that acts on the ball if the ball were fixed to the rod at a distance of 33 cm from the axis?

Fc₂ = 4.675 N

Explanation:

r₁ = 12 cm = 0.12 m

Fc= 1.7 N

Fc = mV²/r = m w² r   ( ∴  V= r w )

Fc = m w² r   (1)

As angular speed (w) and mass are constant.

let    m * w² = k   (2)

Put equation (2) in equation (1).

⇒  Fc = m w² r = k * r         ( ∴ m w² = k)

⇒  Fc =k * r     ( 3)

⇒  Fc₁ =k * r₁ = 1.7 N

⇒ k = 1.7/ r  = 1.7 / 0.12  N    ( as r₁=0.12 m )

⇒ k = 14.17

Centripetal force hen the rod is fixed at 33 cm from the axis:

From equation ( 3 )

Fc₂ =  k * r₂

Fc₂ = 14.17 * 0.33 N    ( ∴ r₂ = 0.33 m)

Fc₂ = 4.675 N

area of focus

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.