A2 000-kg sailboat experiences an eastward force of 3 000 n by the ocean tide and a wind force against its sails with a magnitude of 6 000 n directed toward the northwest (45 n of w). what is the magnitude of the resultant acceleration? with steps, .

The magnitude of the resultant acceleration is 2.2

Explanation:

Mass (m) of the sailboat =  2000 kg

Force acting on the sailboat due to ocean  tide is = 3000N

Eastwards means takes place along the positive x direction

Then = 3000N and = 0

Wind Force acting on the Sailboat is  = 6000N directed towards the northwest that means at an angle  45 degree above the negative x axis

Then  

= -(6000N) cos 45 degree = -4242.6 N

 = (6000N) cos 45 degree = 4242.6 N

Hence  , the net force acting on the sailboat in x direction is  

=  - 3000 N + 4242.6 N

=  - 3000 N +4242.6 N

= 1242.6N

Net Force acting on the sailboat in y direction is  

= 0+ 4242.6N

= 4242.6N

The magnitude of the resultant force =

Using pythagorean theorm of 1243 N and 4243 N

4420.8 N

F = ma

=2.2

i think they are all correct

explanation:

they seem good

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.