Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.00 m. a person is standing 12.0 m away from the wall, equidistant from the loudspeakers. when the person moves 1.00 m parallel to the wall, she experiences destructive interference for the first time. what is the frequency of the sound? the speed of sound in air is 343 m/s

Explanation:

This is a case of interference of sound , akin to YDSE in optics .

Here,  like interference dark and bright fringes, region of silence and intense sound will be formed  due to destructive and constructive interference respectively.

Here d = distance between two sources = 5 m

D = distance of source and screen = 12m

position of first destructive interference

= λ D /2d

1 =  λ 12 /2x 5

λ = 5 / 6  m

frequency = v / λ

= 343 x 6/ 5

= 411.6 Hz

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm