One long wire lies along an x axis and carries a current of 43 a in the positive x direction. a second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 a in the positive z direction. what is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?

Bnet=1.006*10^-6T

Explanation:

One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?

the magnetic field Bnet=

the magnetic field due this long wire is given by

B1=∨I1/..............................1

B2=∨I2/............................2

Bnet=.......................3

Bnet=v/2*pi

Bnet=4*pi*10^-7/(2)

Bnet=0.0000002*(641.72)^.5

Bnet=1.006*10^-6T

whichever one it is, it's definitely not one that you included on the list you provided.