Male rana catesbeiana bullfrogs are known for their loud mating call. the call is emitted not by the frog's mouth but by its eardrums, which lie on the surface of the head. and, surprisingly, the sound has nothing to do with the frog's inflated throat. if the emitted sound has a frequency of 262 hz and a sound level of 84 db (near the eardrum), what is the amplitude of the eardrum's oscillation? the air density is 1.21 kg/m3 and the speed of sound is 346 m/s.

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

divide the right side by the left side

0.024÷1.2=0.02 for example

2b2t

explanation:

2b2t