An electromagnetic wave has a frequency of and is traveling in a vacuum. the magnetic field is given by

(a) find the wavelength and the direction of propagation of this wave.
(b) find the electric field vector.
(c) determine the poynting vector, and use it to find the intensity of the wave.

c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave

Explanation:

An electromagnetic wave carries energy that is given by the vector of poyntíng

     S = 1 / μ₀ E x B

The electric and magnetic fields are related

     E = c B

Substituting

     S = c /μ₀ B² / 2

The two comes from the average value

Let's examine the claims

a) false to determine the wavelength the frequency is needed

b) False. To find the electric field you need the magnetic field

c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave

frequency or wavelenth of em radiation in a vacuum

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.