Aplastic block of mass 0.20.2kg is initially at rest on a horizontal frictionless surface. a bullet of mass 1212 g is fired with an initial speed of 550550m/s towards the block. the bullet passes completely through the block and exits the other side with a speed of 20.020.0m/s. what percent of the initial kinetic energy of the bullet block system is lost during the collision?

94.29619%

Explanation:

= Mass of bullet= 0.012 kg

= Mass of block = 0.2 kg

= Initial Velocity of bullet= 550 m/s

= Initial Velocity of block = 0 m/s

= Final Velocity of bullet = 20 m/s

= Final Velocity of block

As the linear momentum of the system is conserved

Change in kinetic energy is given by

Percentage change is given by

The percent of the initial kinetic energy of the bullet block system is lost during the collision is 94.29619%

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow