Δ→ δ→
5n 6n
what is the net force?

The net force acting on the body, F = 11 N

Explanation:

Given data,

The force acting on the body, f = 5 N

Another force acting on the body, f' = 6 N

The direction of both forces is in the same direction.

The net force is given by the resultant vector,

                                (∵ θ = 0)

                             F = f + f'

                                = 5 N + 6 N

                                = 11 N

Hence, the net force acting on the body, F = 11 N

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards