Two baby buggies are moving toward a head-on collision on level ground. the first buggy has a mass of 12 kg and is moving at a speed of 3 m/s. the second buggy has a mass of 15 kg and is moving at a speed of 5 m/s. the buggies are each equipped with rugged rubber bumpers that insure the collision is perfectly elastic.

which of the following is closest to the distance between the buggies 3 seconds after the collision? (you may neglect friction.)

10 m
15 m
20 m
25 m
30 m

The distance between the buggies is 25 m.

(d) is correct option.

Explanation:

Given that,

Mass of first buggy = 12 kg

Speed of first buggy = 3 m/s

Mass of second buggy = 15 kg

Speed of second buggy = 5 m/s

Time = 3 sec

We need to calculate the final velocity of first buggy

Using formula of velocity

Put the value into the formula

We need to calculate the final velocity of second buggy

Using formula of velocity

Put the value into the formula

The velocity separation will be 2 m/s.

We need to calculate the distance for first buggy

Using formula of distance

Put the value into the formula

We need to calculate the distance for second buggy

Using formula of distance

Put the value into the formula

Total distance between both buggies

Put the value into the formula

Hence, The distance between the buggies is 25 m.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14