We've seen that bees develop a positive charge as they fly through the air. when a bee lands on a flower, charge is transferred, and an opposite charge is induced in the earth below the flower. the flower and the ground together make a capacitor; a typical value is 0.60 pf. if a flower is charged to 30 v relative to the ground, a bee can reliably detect the added charge and then avoids the flower in favor of flowers that have not been recently visited approximately how much charge must a bee transfer to the flower to create a 30 v potential difference?

To solve the problem it is necessary to apply the concept of Load on capacitors. The charge Q on the plates is proportional to the potential difference V across the two plates.

It can be mathematically defined as:

Q= CV

Where,

C = Capacitance

V = Voltage

Our values are given as,

Substituting values in the above formula, we get

Where

Therefore the charge must be 18pC to create a 30V Poential difference.

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong