Calculate the partial pressure of helium gas for a volume of 1.0 x 10^-6 m^3 of 212rn gas after 91 minutes. the radon gas was originally placed in an evacuated container at 1 atm, and the temperature remains constant at 0°c. (t1/2 = 23.9 min for 212rn.)
what is the partial pressure of the radon gas after this time?

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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