Alarge building has an inclined roof. the length of the roof is 54.0 m and the angle of the roof is 17.0° below horizontal. a worker on the roof goes of a hammer from the peak of the roof. starting from rest, it slides down the entire length of the roof with a constant acceleration of 2.87 m/s2. after leaving the edge of the roof, it falls a vertical distance of 46.5 m before hitting the ground.
a. how much time does it take the hammer to fall from the edge of the roof to the ground?
b. how far horizontally does the hammer travel from the edge of the roof until it hits the ground?

a)

b)

Explanation:

Given:

length of inclined roof,

inclination of roof below horizontal,

acceleration of hammer on the roof,

height from the lower edge of the roof,

Now, we find the final velocity when leaving the edge of the roof:

Using the equation of motion:

The direction of this velocity is 17° below the horizontal.

∴Vertical component of velocity:

a.

So, the time taken to fall on the ground:

here:

initial velocity,

putting respective values

b.

Horizontal component of velocity,

Since there is no air resistance so the horizontal velocity component remains constant.

∴Horizontal distance from the edge of the roof where the hammer falls is given by:

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards