6. an object is spun around in a circle of radius 3.0 m with speed of 3.77 m/s. what is its acceleration?
@1.25 m/s2 b. 4.74 m/s2 c. 0.79 m/s2 d. 2.39 m/s2
7. a 5.0 kg object is spun around in a circle of radius 2.5 m with speed of 4.5 m/s. what is its
centripetal force?
fa 9.0n
b. 2.8 n
c. 40.5 n
d. 45 n

6.  Acceleration = 4.74 m/s^2

7.  Centripetal force = 40.5 N

Explanation:

Problem 6.

Recall that the centripetal acceleration is defined as: , where V is the object's tangential velocity, and r the radius of the circular motion. Therefore, in or case, the centripetal acceleration would be:

which we can round to 4.74 m/s^2 (option b in your list)

Problem 7.

Now we need to find not just the centripetal acceleration using the same formula as above, but then the centripetal force.

Now we calculate the centripetal force by multiplying this acceleration times the mass of the object following the definition of force as mass times acceleration:

Centripetal force = 5.0 kg * 8.1 m/s^2 = 40.5 N

The answers comes in Newtons (N)

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

c

explanation: