![F=G*\frac{m_{1}*m_{2} }{r^{2} } \\replacing the values we have\\F=6.67*10^-11*\frac{70*7.35*10^{22} }{ (3.82*10^{8})^{2} } \\F=0.00235[N]](/tpl/images/0422/2400/56269.png)
As a 70-kg person stands at the seashore gazing at the tides (which are caused by the moon),
h...
Physics, 17.12.2019 08:31 BrainzOli7408
As a 70-kg person stands at the seashore gazing at the tides (which are caused by the moon),
how large is the gravitational force on that person due to the moon? the mass of the moon is
7.35 x 1022 kg, the distance to the moon is 3.82 * 108 m, and g = 6.67 x 10-11 nm2/kg2.
Answers: 2
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