Two skaters skate toward each other, each moving at 3.3 m/s. their lines of motion are separated by a perpendicular distance of 1.5 m. just as they pass each other (still 1.5 m apart), they link hands and spin about their common center of mass. what is the rotational speed of the couple about the center of mass? treat each skater as a point particle, each with an inertia of 51 kg.

4.4 rad/s

Explanation:

When the 2 skaters is spinning with a distance of 1.5m, their rotation radius is half of that distance, which is 1.5/2 = 0.75m.

Then their moments of inertia, given that their mass being 51 kg, is (treating them as point mass particle):

When they change from linear motion to rotational motion, their energy must be conserved:

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards