600-g of ice at −15℃ is in a calorimeter when 100 g of water at 20℃ is added to it. water cools down and part of it freezes as a result. find the mass of the remaining liquid water. neglect the heat capacity of the calorimeter. [ = 0.5 cal/g/℃ = 2090 j/kg/℃, = 1 cal/g/℃ = 4186j/kg/℃, = 79.7 cal/g = 3.33 × 10⁵ j/kg]

Explanation:

Given:

According to question a part of water freezes while the other remains liquid:

So,

final temperature of the mixture,

Now using the equation of heat:

Heat required by the total ice of given temperature to melt completely:

.....................................(1)

Heat released by the total mass of given water to come to freezing point:

...............................................(2)

Now from the eq. (1) & (2) the difference in heat is equivalent to the mass of water frozen.

Now the mass of water frozen:

of more ice is formed from the water.

Mass of remaining liquid:

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: