Compute the reactance of a 0.450 h inductor at the frequency of 60.0 hz.

169.65 Ω

Explanation:

Given:

Inductance L = 0.450 H

Frequency F = 60.0 Hz

                          Inductive reactance = ωL

ω is the angular frequency = 2πf

                       ∴ Inductive reactance = 2πfL

Substituting the values of frequency f, inductance L and constant π into the equation above;

                              = 2× π × 60 × 0.450

                             Inductive reactance  = 169.65 Ω  

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000