Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the earth’s magnetic field which is horizontal, perpendicular to the wire, and of magnitude 5.0x10-5 t. what current would the wire carry? does the answer seem feasible? explain briefly.

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

Where,

B = Magnetic Field

I = Current

L = Length

Note:  is a direct adaptation of the vector relation

From Newton's second law we know that the relation of Strength and weight is determined as

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

Our values are given as,

Diameter

Radius

Magnetic Field

From the relationship of density another way of expressing mass would be

At the same time the volume ratio for a cylinder (the shape of the wire) would be

Replacing this two expression at our first equation we have that:

Re-arrange to find I

We have for definition that the Density of copper is , gravity acceleration is and the values of magnetic field (B) and the radius were previously given, then:

The current is too high to be transported which would make the case not feasible.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.