Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. each elevator has a mass of 1,000 kg. the first elevator can do this work in 5.0 seconds. calculate the power output of the first motor.
2.0 x 102 w
2.0 x 103 w
2.0 x 104 w
2.0 x 105 w

Power output =

Explanation:

Given:

Mass of the elevator is,

Height to which it is raised is,

Acceleration due to gravity is,

Time taken by the motor to raise the elevator is,

Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.

Increase in gravitational potential energy is given as:

Therefore, work done by motor is,

Now, we know that, power is work done in unit time. So, power output is given as:

Therefore, the power output of the first motor is

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

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