Aman pushes on a 12kg object for 10 seconds. it moves 8 m to the right while he is pushing it.
a. calculate the acceleration of the mass
b. now use f=ma to calculate the magnitude of the man's force.
c. if the surface is frictionless, how does v3 compare to v2? why?
d. if the surface has friction, how does v3 compare to v2? why?

Explanation:

So for part a you know:

mass: irrelevant for first part

time

distance traveled

And i believe you can assume it starts at rest

So use x= v0t + 1/2at^2

8= 0(10) +1/2a(10)^2

So simplifying the first part of the equation becomes zero and the next part become 50a

Leaving you with 8=0+50a

so a =8/50

Part B

use f=ma to solve the force

f= (12kg) * (8/50)= 1.92

Par c and d im not sure what you mean by v2 and v3

Hope this at least helped with the first two parts

and 1and 1