A70.0 kg stuntman is attached to a bungee cord with an unstretched length of 15.0 m. he jumps off a bridge spanning a river from a height of 50.0 m. when he finally stops, the cord has a stretched length of 44.0 m. treat the stuntman as a point mass, and disregard the weight of the bungee cord. assuming the spring constant of the bungee cord is 71.8 n/m, what is the total potential energy relative to the water when the man stops falling?

The total potential energy is 34.307 kJ

Solution:

As per the question:

Mass of the stuntman, m = 70.0 kg

Length of the unstretched cord, l = 15.0 m

Height of the cord, H = 50.0 m

The stretched length of the cord,

Spring constant of the cord, k = 71.8 N/m

Now,

The total potential energy is given as the sum of gravitational potential energy and elastic potential energy:

The height attained, h = H - = 50.0 - 44.0 = 6.0 m

PE_{G} = mgh =    

Now, the elastic potential energy:

x = l - = 44.0 - 15.0 = 29.0 m

The Total Potential Energy:

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360seconds i 1 hr