Alaser with wavelength d/8 is shining light on a double slit with slit separation 0.500 mm. this results in an interference pattern on a screen a distance l away from the slits. we wish to shine a second laser, with a different wavelength, through the same slits. what is the wavelength λ of the second laser that would place its second maximum at the same location as the fourth minimum of the first laser, if d = 0.500 mm?

0.000109375 m

Explanation:

d = Distance between grating = 0.5 mm

m = Order

Minima relation

For fourth order minima

For second maxima

From the two equations we get

The wavelength is 0.000109375 m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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are there options? cause you ain’t. real specific