The ends of two fixed rods an and b are each made in the form of a single threaded screw of mean radius 6mm and pitch 2mm. rod a has a right handed thread and rod b has a left handed thread. the coefficient of static friction between the rods and the rods and the threaded sleeve is 0.12. determine the magnitude of the couple that must be applied to the sleeve in order to draw the rods closer

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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0.11 m/s and 0.28 m/s should be correct

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.