An suv with a mass of 1.80 103 kg is travelling eastbound with a speed of 15.0 m s while a compact car with a mass of 9.00 102 kg is travelling westbound at 15.0 m s the vehicles collide head on and stick together what is the speed of the wreck immediately after the collision and which way does it move

5 m/s

Explanation:

mass of SUV (M1) = 1.80 x 10^{3} kg = 1800 kg

velocity of SUV (V1) = 15 m/s

mass of car (M2) = 9 x 10^{2} kg = 900 kg

velocity of car (V2) = 15 m/s

let the  direction of motion eastward ( to the right ) be positive while the direction of motion westward (to the left ) be negative, therefore

velocity of SUV (V1) = 15 m/s

velocity of car (V2) = -15 m/s

now applying the conservation of momentum

(M1)(V1) + (M2)(V2) = (M1 + M2) x Vf

where Vf is the final velocity after collision

(1800 x 15) + (900 x (-15)) = (1800 + 900) x Vf

27000 - 13500 = 2700Vf

13500 = 2700 Vf

Vf = 5 m/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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