(a) calculate little g on the surface of the sun. (b) now, say 90 kg b is in an elevator on the sun with the international scale and the elevator is accelerating down at 25 ge , where ge = 10 m/s 2 . what does the scale display? use g = 6.67 ⨉ 10 -11 n m2 /kg 2 , sun mass: 2 ⨉ 10 30 kg, sun radius: 700,000 km.

Answer

a) to find the acceleration due to gravity of sun

m is mass of sun = 2 x 10³⁰ Kg

    R is the radius =  700,000 km = 7 x 10⁷ m

             g = 272.24 m/s²

b) mass of the man = 90 Kg

  acceleration = 25 g

reading of scale on sun

        m' = 7.35 Kg

question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation: