Calculate the average speed of the moon around the earth. the moon has a period of revolution of 27.3 days and an average distance from the earth of 3.84 × 108 m. 1. 2054.6 m/s 2. 2045.8 m/s 3. none of these 4. 8.83789 × 107 m/s 5. 3688.5 m/s 6. 3.68245 × 106 m/s 7. 1022.9 m/s 8. 584000 m/s 9. 61374.2 m/s

Average speed, v =1022.90 m/s

Explanation:

Given that,

The average distance between the moon and the earth is,

The period of revolution of the Moon,

To find,

The average speed of the Moon around the Earth.

Solution,

If T is the orbital period and r is the orbital speed of the moon. The average speed is given by :

Where

is the angular speed

Since, 1 day = 86400 seconds

27.3 days = 2358720 seconds

v = 1022.90 m/s

or

So, the average speed of the Moon around the Earth is 1022.90 m/s.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m