Following vigorous exercise, the bodytemperature ofan bod-kg person is 400°c . at what rate in watts must the persontransfer thermal energy to reduce the the body temperature to 370°c in 30.0 min, assuming the body continues toproduce energy at the rate of 150 w? [1 watt = 1joule/second or 1 w = 1 j/s).

The rate of transfer of the thermal energy is 616.67 W

Solution:

As per the question:

Temperature of the person after exercise,

After the temperature is reduced,

Time taken, t = 30 min = 1800 s

Mass, m = 80.0 kg

Now,

The rate of transfer of thermal energy by the person can be calculated as:

Heat energy, Q =

The rate of transfer of energy gives the power:

P =

Total Power, P' = P + 150 = 466.67 + 150 = 616.67 W

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.