(a) calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 28.8 m. assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kpa.

383828 Pa

Explanation:

= Atmospheric pressure =

= Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 28.8 m

Absolute pressure is given by

The absolute pressure at the bottom of the fresh water lake is 383828 Pa

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explanation:

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow