Ablock with an initial kinetic energy of 4.0 j comes to rest after sliding 1.0 m. how far would the block slide if it had 8.0 j of initial kinetic energy?

2.0 m

Explanation:

Kinetic Energy: This is the energy of a body due to motion.

According to the law of conservation of energy,

Kinetic Energy = potential Energy = mgs

Where m = mass (kg) , g = acceleration due to gravity (m/s²) , s = distance or height (m).

Kinetic energy = 4.0 J , s = 1.0 m , g= 9.8m/s² , m=?

∴ m = kinetic Energy/(gs)

 m = 4/(1 ×9.8) = 0.4081 Kg.

When the initial kinetic energy  8.0 J

∴ Distance (s) = 8.0/(0.4081 × 9.8)

    Distance (s) = 2.00031

     Distance (s) ≈ 2.0 m

∴  the block would slide 2.0 m

true tan speed = ang vel x radius