Physics, 10.12.2019 04:31 nonjabulomabaso7423

Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 × 1014 hz. the speed of light is 3.00 × 108 m/s. and

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Answer from: Dweath50

The wavelength of blue-light is $2.064 \times 10^{32} \;\rm m$ .

Explanation:

Given data:

The frequency of light is, $f=6.88 \times 10^{14} \;\rm Hz$ .

The speed of light is, $c=3.00 \times 10^{8} \;\rm m/s$ .

The expression for the frequency of light is,

$f= \dfrac{c}{ \lambda}$

Here, $\lambda$ is the wavelength of light.

Solve by substituting the values as,

$6.88\times 10^{14}= \dfrac{3.00 \times 10^{8}}{ \lambda}\\\lambda = (6.88\times 10^{14}) \times (3.00 \times 10^{8})\\\lambda =2.064 \times 10^{23} \;\rm m\\\lambda = 2.064 \times 10^{23} \times 10^{9} \\\lambda = 2.064 \times 10^{32} \;\rm nm$

Thus, the wavelength of blue-light is $2.064 \times 10^{32} \;\rm nm$ .

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Answer from: crysmrod

430 nm.

Explanation:

The relation of wavelength and frequency is:

Formula used : $\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency = $6.88\times 10^{14}Hz$

$\lambda$ = wavelength = ?

c = speed of light = $3.00\times 10^{8}m/s$

Now put all the given values in this formula, we get

$6.88\times 10^{14}=\frac{3.00\times 10^{8}m/s}{\lambda}$

$\lambda=\frac{3.00\times 10^{8}m/s}{6.88\times 10^{14}}=0.43\times 10^{-6}m=430m$ $(1nm=10^{-9}m)$

Thus the wavelength (in nm) of the blue light emitted by a mercury lamp is 430 nm.

Answer from: Quest

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Answer from: Quest

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Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.8...

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