Consider two isolated conductive metal spheres. each carries the same amount of excess charge +q, but one has a radius that is five times greater than the other.

how does the electrostatic potential of the two spheres compare?

Electric potential of the second conductive metal sphere will be times than first conductive metal

Explanation:

We have given that there are there are two isolated conductive metal surfaces each have charge +Q

And one has radius 5 times greater than second

Now we know that electric potential due to conducting sphere

As from the relation we can see that electric potential is inversely proportional to the radius of the sphere

So electric potential of the second conductive metal sphere will be times than first conductive metal

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: