Acar traveling on a straight road at 15.0 meters per second accelerates uniformly to a speed of 21.0 meters per second in 12.0 seconds. the total distance traveled by the car in this 12.0-second time interval is ) 36.0 m (3) 216 m(2) 180. m (4) 252 m

Explanation:

We have initial velocity, u = 15 m/s

Time, t = 12 seconds

Final velocity, v = 21 m/s

We have equation of motion v = u + at

Substituting

                     21 = 15 + a x 12

                       a = 0.5 m/s²

Now we have equation of motion v² = u² + 2as

                           21² = 15² + 2 x 0.5 x s

                            s = 216 m

       Displacement = 216 m

Option 3,  216 m is the correct answer.

c)as speed changes, wavelength and frequency change.

everything changes!

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~