Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿cuál es la longitud del camino recorrido al cabo de 3.0 segundos? porfa es para mañana

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

The length of the path traveled after 3.0 seconds is 25.9 meters

Explanation:

Given that,

A body moves in a straight line according to the equation,

........(1)

Here, x is in meters and t is in seconds

We need to find the length of the path traveled after 3.0 seconds. To find it, simply put the value of t as 3 seconds in equation (1).

So, the length of the path traveled after 3.0 seconds is 25.9 meters. Hence, this is the required solution.

answer: b.

explanation:

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6