Ball a is allowed to fall and strike ball b. assume that all of ball a's energy is transferred to ball b at point i, and that there is no loss of energy to other sources. determine the kinetic energy of ball b at point ii.

Explanation:

If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B

Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A

K. E = T. E - P.E

Incomplete question:

mA = 4 kg

h point I = 5 m

mB = 2 kg

h point II = 2 m

the kinetic energy of ball B at point II is 156.8 J

Explanation:

the solution is in the attached Word file

area of focus

your answer is, orbit around the nucleus