Ablock with mass m =6.4 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.28 m. while at this equilibrium position, the mass is then given an initial push downward at v = 5.1 m/s. the block oscillates on the spring without friction.
1)what is the spring constant of the spring?
2)what is the oscillation frequency?
3)after t = 0.42 s what is the speed of the block?
4)what is the magnitude of the maximum acceleration of the block?
5)at t = 0.42 s what is the magnitude of the net force on the block?

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

    k x = m g

      k = 224 N/m

b)

c)  

d)  

e)  

        A = 0.682 m

Force =

          =

F = 94.20 N

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

this is a good question! i'll do some research and come back when i have the answer!