Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 28.0 ∘c and the pressure is constant. part aas part of a machine design project, calculate the final temperature of the gas after it has done 1770 j .express your answer using three significant figures.

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

Where, P is the pressure

is the change in volume

Also,

Considering the ideal gas equation as:-

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 8.314 J/ K mol

So,

Also, for change in volume at constant pressure, the above equation can be written as;-

So, putting in the expression of the work done, we get that:-

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

n = 6 moles

So,

Thus,

The temperature in Celsius = 336.63-273.15 °C = 63.5 °C

The final temperature is:- 63.5 °C

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form