Auniform beam is suspended horizontally by two identical vertical springs that are attached between the ceiling and each end of the beam. the beam has mass 225 kg, and a 175-kg sack of gravel sits on the middle of it. the beam is oscillating in shm, with an amplitude of 40.0 cm and a frequency of 0.600cycles/s. part a the sack of gravel falls off the beam when the beam has its maximum upward displacement. what is the frequency of the subsequent shm of the beam?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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